Divide distance with time
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.
I think eight because if you add those days together they will play again in eight days so that they play on the same day.
Sorry if I got it wrong I tried and that's what counts, right?
Answer:
The best estimate for the solution is the ordered pair 
Step-by-step explanation:
we have
------> equation A
------> equation B
we know that
using a graphing tool, the solution of the system of equations is the intersection point both graphs
The intersection point is 
therefore
The best estimate for the solution is the ordered pair
Answer:
y-intercept = 4
x-intercept = 2
Step-by-step explanation:
you can divide the equation through by 4 and change into the y=mx+c form to find c, the y intercept so the y-intercept = 4.
for the x intercept make the y=0 (because the coordinate point where the line crosses the x axis must have y=0) and then you get 8x=16 so x=2
