This is a simple average problem- the average per student in mr brown's versus average per student in mr garcias.
brown
72/24 =3
garcia
98/28 = 3.5
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
Step-by-step explanation:
We say that a function is differentiable if it's derivative exists and it is continous over the domain of the original function. Recall that the function |x| is given as |x| = x if and |x|=-x if x<0. In both cases, we have either the function x or -x, which are one-degree polynomials. So, we can find easily their derivatives. So if f(x) = |x|. Then, we have that
We should check what happens x=0, since that is the point where the definition of f changes. We can check that
and
since this limits are not equal, the derivative is not continous at x=0. Hence, the derivative doesn't exist at x=0.
In this case, we say that |x| is differentiable at any x different from 0.
Answer:
it will take 3 5/8 of gas to fill the tank
Step-by-step explanation:
14 1/2 - 10 7/8 can be re-written using improper fractions
29/2 - 87/8 We need a common denominator, which is 8
116/8 - 87/8 = 29/8 = 3 5/8 gal
Answer:
Answer is A
Step-by-step explanation:
My hand wont support me