Answer:
x = 4
Step-by-step explanation:
doesn't pass the vertical line test
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, is equal to , thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, . Since a and b were generic elements of H, then H/G is abelian.
Answer:
See below.
Step-by-step explanation:
1.) False - It contains 6 sig figs, not 2.
2.) False - It goes up to 2 decimal places, not 3.
3.) True
4.) False - It goes up to 1 sig fig, not 4.
Answer:
Step-by-step explanation:
subtract by 5 on both sides. ur left with
square root b and 16. the square root cancels out b squared. find the square root of 16. the square root of 16 is 4
Answer: i think the answer is -3
Step-by-step explanation: