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Olegator [25]
3 years ago
6

Does anyone know the answer to this question?pic is shown

Mathematics
2 answers:
erica [24]3 years ago
6 0
1/6 can be be 4/24, 1/3 can be 8/24, and 1/4 can be 6/24. Add them together and you get 18/24, then do 1 (or 24/24) minus 18/24 which equals 6/24 or 1/4
diamong [38]3 years ago
5 0
She still has 1/4 of her allowance.
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Use the formula for the present value of an ordinary annuity or the amortization formula to solve the following problem. PV=​$20
White raven [17]
Assuming monthly payment of $250, which implies APR=0.01*12=0.12.
If it is different, please specify.

target P=20000,
A=250
n=to be determined such that P>=target P=20000
The annuity equation with given (monthly) payment is given by
P=250(P/A,i,n)
=A((1+i)^n-1)/(i(1+i)^n)
=250(1.01^n-1)/(0.01(1.01)^n)
=25000(1.01^n-1)/(1.01^n)
Solve for n by trial and error,
Rewrite 
20000<=25000(1-1/1.01^n)
=>
1.01^n>=25000/20000=1.25
Take log on both sides,
n*log(1.01)>=log(5)
n>=log(5)/log(1.01)=161. 75
=> n=162 (next integer)
Check:
P=250(P/A,0.01,162)=250*(1.01^162-1)/(.01*1.01^162)=20012.56 ok.
8 0
3 years ago
The book store is having a sale where all hardcover books are 20% off. Jamie also has a coupon for 15% off any fiction book. Jam
Dmitry_Shevchenko [17]
<span>Jamie bought a hand cover fiction book with $32.99 price.
She has a coupon that has a 15% off.
The store offers 20% off
x= how much will she save?

=> 20% = 20/100
=> .20
=> 15% = 15/100
=> .15
=> .20 + .15
=> .35

=> The amount is 32.99, multiply this by .35
=>  32.99 x .35
=>  11.5465 – She saved $11.55
=>  32.99 – 11.5465
=> 21.4435 – She only paid 21.4435 for her hand cover fiction book that she bought.</span> <span>

</span>



5 0
3 years ago
Read 2 more answers
 K is the midpoint of . if = 3x + 1 and     , find the length of
jarptica [38.1K]
3x + 1 = 1/3x + 9 Multiply through by 3 
<span>9x + 3 = x + 27 Subtract x </span>
<span>8x + 3 = 27 Subtract 3 </span>
<span>8x = 24 </span>
<span>x = 3 </span>

<span>AK = 3*3 + 1 = 10 </span>

<span>AB = 2*AK = 20</span>
4 0
3 years ago
If the streets of a city are straight lines and the intersections are points, show how Principle 2 and Principle 3 might be illu
Naily [24]

Step-by-step explanation:

In the plane geometry Abeka, second edition, it is given :

Principle 2 states that between any two points, only one straight line can be drawn.

And according to principle 3 two straight lines interacts at one point only.

Thus this can be well illustrated by two straight lines which are represented by the streets of a city and these two streets intersects at a point.

6 0
3 years ago
Help me pls. So what is 8y-I​
adell [148]

Answer:

In this problem, "y" represents the integer that must be found or figured for. When a number and a representation are written this way, i.e. "8y", you must mulitply them. If there is more information, you can figure for "y". If there is no other information, "y" is simplied and the end result is "8y".

And I not sure what - 1 is but it might be subtraction.

3 0
3 years ago
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