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myrzilka [38]
3 years ago
9

True or false? Peptidoglycan is a polysaccharide found only in bacteria.

Biology
1 answer:
Trava [24]3 years ago
6 0
It’s True..................
......
.........
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Classification od hornwort​
miv72 [106K]

Answer:  Traditionally, hornworts have been classified as bryophytes, together with mosses (division Bryophyta) and liverworts (division Marchantiophyta). In some classification systems, hornworts have been grouped as horned liverworts in the subclass Anthocerotidae (class Hepaticae), class Anthocerotopsida, order Anthocerotales.

Explanation: Yw and pls mark me brainiest

7 0
2 years ago
Which three of the following statements accurately describe the blood buffering system in humans? the blood buffering system . .
Bogdan [553]
The truth about blood buffering is that 1). mantains the ph of blood near to 7.4. 2) utilizes the H2CO3/HCO3– conjugate acid/base pair and 3) is facilitated by the enzyme carbonic anhydrase, which interconverts carbon dioxide and water to carbonic acid. Have in mind that the buffer is written as the following: <span>CO2(aq) + H2O(l) <==> H+(aq) + HCO3^-(aq) </span>
8 0
3 years ago
Hershey and Chase used a DNA-based virus for their work. How might the results have been different if they had used an RNA virus
4vir4ik [10]

Answer:

The correct answer is c.With an RNA virus, radioactive RNA would have been in the final pellet.

Explanation:

Hershey and Chase infected<em> E.coil</em> with bacteriophage which was having DNA as its genetic material. The bacteriophage was labeled with radioactive sulfur and radioactive phosphorus and it was radioactive phosphorus that was found in the bacterial cells or pellet.  

As because DNA contains phosphorus, not protein therefore they it was proved that DNA is the genetic material. Similarly, RNA is also a nucleic acid which is genetic material for many viruses and contains phosphorus.

So if Hershey and chase might have chosen an RNA virus then radioactive RNA would have been present in the pellet. So the correct answer is c.

7 0
3 years ago
(b) Based on the data for the groups of cells cultured with 0.1% serum (groups 3 to 7), identify the groups(s) most likely to in
joja [24]

Answer:

Groups 4 to 7 are most likely to be undergoing the mitotic phase of the cell cycle.

Explanation:

Since the four proteins used p16,  p18,  p21, and  p27 are inhibitors of cyclin-dependent kinases (CDK), their absence indicates that the cell is undergoing mitosis - the cell cycle is regulated by CDKs. In the absence of these inhibitors, the cell cycle moves on forward. Because the bar for DNA replication is longer in the case for groups 4 to 7, it is indicative of the fact that these cells have gone through the mitotic phase.

Hope that answers the question, have a great day!

4 0
3 years ago
How does the carrying capacity of the ecosystem for the white footed mouse respond to the changes in the amount of parasites? Co
9966 [12]

Answer:

See the answer below

Explanation:

<em>The carrying capacity of the ecosystem for the white-footed mouse reduced in response to the changes in the amount of worm infected mice in the population.</em>

The carrying capacity of an ecosystem for a particular population of organisms is the maximum number of organisms the ecosystem can support based on the resources it has.

<u>The ideal carrying capacity of the ecosystem for the white-footed mouse oscillates between 36 to 40 in graph 1. The carrying capacity range reduced in graph 2 from 36 - 40 to 30 - 36 as a result of changes made to the number of mice infected with parasitic worms in the population of the animal. </u>

Thus, the introduction of more worm-infected mice into the population probably put more pressure on the ecosystem resources thereby reducing the carrying capacity.

3 0
3 years ago
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