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3 years ago

Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?

Mathematics

2 answers:

jeka57 [31]3 years ago

5 0

Answer:

2 whole 1/4

Step-by-step explanation:

When forming a perfect square trinomial you need to "complete the square".

All of the steps to completing the square when solving an equation:

1. The leading coefficient must be 1.

2. Divide b by 2.

3. Square (b/2)

4. Add (b/2)^2 to both sides to keep the polynomial balanced.

5. You can now write the perfect square trinomial and solve.

x^2 - 3x

-3/2

(-3/2)^2 = 9/4 = 2 1/4

hjlf3 years ago

5 0

Answer:

The answer is 2 1/4

Step-by-step explanation:

You are welcome.

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3 years ago

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

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Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

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