Subtract the following polynomials
1 answer:
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Answer:
<h2>Check out the image.</h2>Step-by-step explanation:
Let, the equation of the straight line is y = mx + c; where m is the slope of the equation and c is the constant.
The line has the slope 1.
Hence, the equation becomes y = x + c.
Since, the line passes through (-6, -2), -2 = -6 + c or, c = 4.
Hence, the equation of the straight line becomes y = x + 4.
Putting x = 0, we get, y = 4.
The line passes through (0, 4).
Answer:
The equation of the straight line is 4x +y = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are (-1,5) and ( 2,-7)
Slope of the line
slope of the line m = -4
<u><em>Step(ii):-</em></u>
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4
y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
<u><em>Final answer:-</em></u>
The equation of the straight line is 4x +y = 1
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