Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Compatible numbers to find two estimates 73÷4,858
70÷4,850 = 0.014
You sure it's not 4,858÷73
4,850÷70 =
______ _____ 69 2/7
70)4850. 7)485
42
65
63
Y = 2x/x-7
x = 2y/y-7
xy - 7x = 2y
-7x = 2y - xy
-7x = y(2-x)
y = -7x / 2-x
y = 7x / x-2
f-¹(x) = 7x / x-2
total distance travelled=72+69=141
time taken in hours for journey= (48/60)h + (69/60)= 1.95 h
average speed=141km/1.95h= 72.3km/h (3 sf)
A little more info please?
