Answer: it will take them 28 minutes to fill the tank.
Step-by-step explanation:
The first pipe alone can fill the tank in 84 minutes. This means that the rate at which the first pipe fills the tank per minute is 1/84
The second pipe can fill the tank in 42 minutes by itself. This means that the rate at which the second pipe fills the tank per minute is 1/42
If they work together, they would work simultaneously and their individual rates are additive. This means that their combined rate of filling the tank would be
1/84 + 1/42
Assuming it takes t hours for both pipes to fill the tank working together, the working rate per minute would be 1/t. Therefore,
1/84 + 1/42 = 1/t
3/84 = 1/t
t = 84/3
t = 28 minutes
Step 1: Line up the equations so that the variables are lined up vertically.
Step 2: Choose the easiest variable to eliminate and multiply both equations by different numbers so that the coefficients of that variable are the same.
Step 3: Subtract the two equations.
Step 4: Solve the one variable system.
Step 5: Put that value back into either equation to find the other equation.
Step 6: Reread the question and plug your answers back in to check.
Answer:
length of the longest pencil that can fit must be less than 13cm
Step-by-step explanation:
To get the longest pencil that fit the case, we will use the pythagoras theorem;
diameter = 10cm
radius = 10/2
radius = 5cm
Height = 12cm
Get the length of the longest side
l² = r²+h²
l² = 5²+12²
l² = 25 + 144
l² = 169
l = √169
l = 13cm
Hence the length of the longest pencil that can fit must be less than 13cm
Step-by-step explanation:
the derivative of an inverse function is
1/f'(f^-1(x))
f'(x) = -6x²
f^-1(7) is solving the original function equation for x under the knowledge that y = 7
7 = 5 - 2x³
2 = -2x³
-1 = x³
=>
x = -1
f'(-1) = -6×(-1)² = -6×1 = -6
so,
(f^-1)'(7) = -1/6
Answer:
Step-by-step explanation:
Given function is,


This function is not defined at "x(x - 2) = 0"
Therefore, for the values of x = 0 and 2, given function is not defined.
Vertical asymptote → x = 2 [Denominator = 0]
For Horizontal asymptote → ![[\frac{2x^2}{-4x^2} =-\frac{1}{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2x%5E2%7D%7B-4x%5E2%7D%20%3D-%5Cfrac%7B1%7D%7B2%7D%5D)
Therefore, horizontal asymptote → y =
x-intercept,
For f(x) = 0,
Numerator of the function = 0
2x² + 6x = 0
2x(x + 3) = 0
x = -3
Therefore, x - intercept → (-3, 0)
For y-intercept,
x = 0
f(0) = 0
Therefore, graph has no y-intercept.
For holes on the graph,
Since, function is not defined at x = 0,
f(x) = 
f(0) = 
= 
Therefore, hole on the graph → 