Answer:
{1,2,3,4} every 1st element of each pair is domain.
Answer:
The given statement is true.
Step-by-step explanation:
In order to inscribe a circle in a triangle, the circle's center must be placed at the incenter of the triangle.
This statement is true.
The INCENTER is the center of the circle that is inscribed in the triangle. Like the centroid, the incenter is always inside the triangle.
(2-7m^6)^2
rearrange terms:
(2-7m^6)^2
(-7m^6 + 2)^2
expand the squares:
(-7m^6 + 2)^2
(-7m^6 + 2)(-7m^6 + 2)
distribute:
(-7m^6 + 2)(-7m^6 + 2)
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
distribute:
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
49m^12 - 14m^6 + 2(-7^6 +2)
distribute:
49m^12 - 14m^6 + 2(-7^6 +2)
49m^12 - 14m^6 - 14m^6 + 4
combine like terms:
49m^12 - 14m^6 - 14m^6 + 4
49m^12 - 28m^6 + 4
solution:
49m^12 - 28m^6 + 4
please mark brainliest and hope it helps
Answer:
3.14159 (pi)
Step-by-step explanation:
1^1=1*3.14=3.14
