The answer is 0
Let's solve your equation step-by-step.
3(|v−3|)=9
Step 1: Divide both sides by 3.
3(|v−3|)3=93
|v−3|=3
Step 2: Solve Absolute Value.
|v−3|=3
We know either v−3=3orv−3=−3
v−3=3(Possibility 1)
v−3+3=3+3(Add 3 to both sides)
v=6
v−3=−3(Possibility 2)
v−3+3=−3+3(Add 3 to both sides)
v=0
Answer:
v=6 or v=0
<u>First remove:</u>
Probability of removing a trained rat is 6/8
Probability of removing untrained rat is 2/8
Outcome is 6/8 + 2/8 = 1
<u>Second remove:</u>
Probability of picking a trained rat is 5/7
Probability of picking untrained rat is 1/7
Outcome is 6/7
<u>Third remove:</u>
Outcome is 1 (Since you can only remove a trained rat)
<u>Forth remove:</u>
Outcome is 1 (Since you can only remove a trained rat)
<u>Fifth remove:</u>
Outcome is 1 (Since you can only remove a trained rat)
Total outcome = 1 + 6/7 + 1 + 1 + 1 = 34/7 = 4(6/7)
ANSWER:
C) -14
step-by-step explanation:
7y - 28 + 28 = 8y - 14 + 28
Answer:
No idea brother good luck
Step-by-step explanation: