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tigry1 [53]
3 years ago
15

Which one is the answer???

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0
D is correct because y on I doesn't equal y on II.
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Solve the equation if 0 degrees&lt;=x&lt;=360 degrees.<br> tanx=sqrt 3
storchak [24]

Answer:

Step-by-step explanation:

hello :

tanx = √3        0°≤x≤360°

x = 60°

x=240°

4 0
3 years ago
Can you find the limits of this ​
Pavel [41]

Answer:

\displaystyle  \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{-3}{8}

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Constant]:                                                                                             \displaystyle \lim_{x \to c} b = b

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Property [Addition/Subtraction]:                                                                   \displaystyle \lim_{x \to c} [f(x) \pm g(x)] =  \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)

L'Hopital's Rule

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

We are given the following limit:

\displaystyle  \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16}

Let's substitute in <em>x</em> = -2 using the limit rule:

\displaystyle  \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{(-2)^3 + 8}{(-2)^4 - 16}

Evaluating this, we arrive at an indeterminate form:

\displaystyle  \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{0}{0}

Since we have an indeterminate form, let's use L'Hopital's Rule. Differentiate both the numerator and denominator respectively:

\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \lim_{x \to -2} \frac{3x^2}{4x^3}

Substitute in <em>x</em> = -2 using the limit rule:

\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{3(-2)^2}{4(-2)^3}

Evaluating this, we get:

\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{-3}{8}

And we have our answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

6 0
3 years ago
If W = 7 units, X = 5 units, Y = 13 units, and Z = 11 units, then what is the approximate perimeter of the object?
Zolol [24]

Answer:

to find the perimeter, you would need to add, so I the answers would be 36 units.

Step-by-step explanation:

5 0
3 years ago
Connie has saved up $15 to purchase a new CD from the local store. The sales tax in her county is 5% of the sticker price. Write
Tom [10]
Assume the price of the CD is x. 
x+0.05x=15
x=14.29
3 0
3 years ago
Read 2 more answers
The equation h(t)=−16t^2+70t+40 gives the height of a toy rocket, in feet, t seconds after it is launched from a platform.
dexar [7]
Here, Function: h(t)= -16t² + 70t + 40

So, put the value of t, (time at which you want to calculate the height)

h(1) = -16(1)² + 70(1) + 40
h(1) = -16 + 110
h(1) = 94

Now, h(2) = -16(2)² + 70(2) + 40
h(2) = -64 + 180
h(2) = 116

h(3) = -16(3)² + 70(3) + 40
h(3) = -144 + 250
h(3) = 106

In short, Your height depends on time, and at each time it would be different, can be expressed by the coordinates on a Graph: (1, 94) (2, 116) (3, 106)

Hope this helps!
6 0
3 years ago
Read 2 more answers
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