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seraphim [82]
2 years ago
14

Percent is a fraction where what parts make one whole.

Mathematics
1 answer:
liberstina [14]2 years ago
8 0

Answer:Percent is a fraction where the denominator is represented by 100 or 100 parts make one whole.

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Which function below is the inverse of f(x)= 3x+5/7
Ipatiy [6.2K]
Inverse
replace f(x) wih y
solve for x
replace x with f⁻¹(x) and y with x

so

f(x)=3x+5/7
replace
y=3x+5/7
solve for x
minnus 5/7 both sides
y-5/7=3x
divide both sides by 3
\frac{y- \frac{5}{7} }{3}=x
replace with f⁻¹(x)

f⁻¹(x)=\frac{y- \frac{5}{7} }{3}
5 0
3 years ago
Read 2 more answers
Which equation shows 6(x + 4) = 2( y + 5) solved for y? A. y = x + 3 B. y = 3x + 5 C. y = 3x + 7 D. y = 3x + 17
UNO [17]

Answer:

C

Step-by-step explanation:

Given

6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation

6x + 24 = 2y + 10 ( subtract 10 from both sides )

6x + 14 = 2y ( divide all terms by 2 )

3x + 7 = y, hence

y = 3x + 7 → C

4 0
2 years ago
a college loan of 15000 has a 3% annual simple interest rate what is the interest the student will pay after 5 years
inessss [21]

Answer:

Interest = $ 90000

Step-by-step explanation:

Given, Principal= $15000

Rate = 3%

Time = 5 years

Interest = P × R × T/100

Therefore, Interest = 15000 × 3 × 5/100

(dividing 100 by 5 to get 20)

= 15000 × 3 × 20

= 90000

if it helps don't forget to like and mark me down

7 0
3 years ago
Can someone help me with this problem??
Crank

Answer:

V = 33.49

Step-By-Step Explanation:

V = 4/3πr³

V = 4/3×π×2³

V = 4/3×π×8

V = 4/3×25.12

V = 33.49333...

Shortened

V = 33.49

4 0
2 years ago
Can someone help me with this problem asap
xenn [34]

Answer:

f(x) = $ x^4 - 2x^3 + 49x^2 - 18x + 360 $ is the required polynomial.

Step-by-step explanation:

Given the zeroes (roots) of the polynomial are $ -3i $ and $ 2 + 6i $.

We know that complex roots occur in conjugate pairs.

So, this means that $ +3i $ and $ 2 - 6i $ would also be the roots of the polynomial.

If $ \pm 3i $ are to be the roots of the polynomial then the polynomial should have been: $ x^2 + 9 = 0$.

Now, to determine the polynomial for which $ 2 \pm 6i $ would be the roots.

Roots of the polynomial are nothing but the values of x (any variable) that would make the polynomial zero.

⇒ $ x = 2 + 6i \hspace{35mm} x = 2 - 6i $

⇒ $ x - 2 - 6i = 0 \hspace{25mm} x - 2 + 6i = 0 $

The required polynomial would be the product of all the above polynomials.

$ i.e., (x^2 + 9)(x - 2 + 6i)(x - 2 - 6i) = 0 $

Multiply this to get the required equation.

⇒$ (x^2 + 9)(x^2 - 2x + 40) $

$ \implies x^4 - 2x^3 + 40x^2 + 9x^2 - 18x + 360 = 0 $

∴ The required polynomial is x⁴ - 2x³ + 49x² - 18x + 360 = 0.

3 0
3 years ago
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