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Rasek [7]
3 years ago
7

HURRY I'LL PICK A BRAINLIEST PERSON!!!

Mathematics
2 answers:
Maurinko [17]3 years ago
7 0
Density = mass/volume
D = m/v
v*d = m
v = m/d
m/d = v

The final answer is choice C
Delicious77 [7]3 years ago
5 0
I'm pretty sure the answer is C. m/d = V. Mass divided by volume equals density.
You might be interested in
Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (
STALIN [3.7K]
Hello,

Vertices are on a line parallele at ox (y=-3)

The hyperbola is horizontal.

Equation is (x-h)²/a²- (y-k)²/b²=1

Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and  2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)

Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6

c²=a²+b²==>b²=36-4²=20

Equation is:
\boxed{ \dfrac{(x-2)^2}{16} - \dfrac{(y+3)^2}{20} =1}





8 0
3 years ago
HELP PLEASE
Hoochie [10]
If you had values instead of algebraic expressions, you would find the area of the patio and subtract that from the area of the yard. Even though you don't have values, you can still find the area and subtract by expanding and simplifying:
(8x + 2)(6x + 3)
8x × 6x = 48x²
8x × 3 = 24x
2 × 6x = 12x
2 × 3 = 6
So you get 48x² + 36x + 6 as your area of the yard

(x + 5)(3x + 1)
x × 3x = 3x²
x × 1 = x
5 × 3x = 15x
5 × 1 = 5
So the area of the patio is 3x² + 16x + 5

(48x² + 36x + 6) - (3x² + 16x + 5)
48x² - 3x² = 45x²
36x - 16x = 20x
6 - 5 = 1

So your answer is D. 45x² + 20x + 1. I hope this helps!

6 0
3 years ago
A test consists of 490 true or false questions. If the student guesses on each question, what is the standard deviation of the n
monitta
I believe the answer is 1.
3 0
3 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
how do you determine if the answer to a problem is negative or positive in division multiplication addition and subtraction
erica [24]
In multiplication, a negative times a positive has a negative answer. if both are positive or both are negative, the answer is positive.
5 * -5 = -25
-5* -5 = 25


in divisions say you have
-5/5 = -1
-5/-5= 1
5/-5= -1


in addition and subtraction, subtracting a negative means to add the two numbers. adding a negative means to subtract the second number.

5+ (-5) = 0
5- (-5) = 10
7 0
3 years ago
Read 2 more answers
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