Answer:
y = 3/4x - 9/8
Then read explanation and see here with 2 coordinates would make
if 3/4 = -6 then 1 = -8
y = -6x + c
-6 / 3/4 + 9/8 / - 0.5 = -2.25
therefore c = -2.25
y = -6x - 2.25
y = -6x - 9/4 and again 9/4 can be found easily if round up fraction decimal to 225/100 and divide by 4
Step-by-step explanation:
C1) (0.5 , -0.75)
C2) ( 1. -3.75)
y = mx + c
-3.75 - - 0.75 / 1 - 0.5 = -3.75 + 0.75 / 0.5
= -3 / 0.5 = m
m = -6
y = -6x + c
then this works given just one coordinate to solve for 1 or 2 sets given points
y - y1 = mx+c
y - - 0.75 = 0.75 (x - x1)
y + 0.75 = 0.75 (x - 0.5)
y + 0.75 = 0.75x - 0.375
y = 0.75 - 0.75 = 0.75x( - 0.375 - 0.75)
y = 0.75x -1.125
y = 3/4x - 9/8 as common denominators of 1125/1000 is 9/8 as we divide by 125 into the fraction as we start at 250 and check its half just like when finding common denominators we 1/4 the lower number and see if we can find its half or its double etc with the other num er as first step for 3sf numbers.
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer: -11 meters
Step-by-step explanation:
so for the waters surface, we are going to call that 0. if bob is at 15 meters below 0, then -15+4=-11, so he would be at-11 meters in relation to the waters surface.
Answer:
r = 12
Step-by-step explanation:
DG + GM = DM , substitute values
r + 3 + 4r - 28 = 35 , that is
5r - 25 = 35 ( add 25 to both sides )
5r = 60 ( divide both sides by 5 )
r = 12
Answer:
N, P
Step-by-step explanation:
The answer is N, and P.
