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2 years ago

Help me with this please

Mathematics

1 answer:

kompoz [17]2 years ago

8 0

Answer: (5.5 , -1.5)

19 + (-8) / 2 = 5.5

15 + (-18) / 2 = -1.5

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Choco-Chippy Cookie Company has two different manufacturing plants. Company officials want to test whether each plant fills the

garik1379 [7]

Answer:

The correct answer is D

Step-by-step explanation:

As it can be clearly visualized from the graph that the variation is not likely to be 2.0 as at most of the points the difference is not close to 2.0

Hence, The difference is not significant because a difference of 2.0 is not very likely.

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2 years ago

Read 2 more answers

2- 10+ x = 6 -8 + 12<br> Please answer ASAP :)

Arisa [49]

Answer: X=18

Step by Step:

2−10+x=6−8+12

Step 1: Simplify both sides of the equation.

2−10+x=6−8+12

2+−10+x=6+−8+12

(x)+(2+−10)=(6+−8+12)(Combine Like Terms)

x+−8=10

x−8=10

Step 2: Add 8 to both sides.

x−8+8=10+8

x=18

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3 years ago

Read 2 more answers

I need help please

Wewaii [24]

Answer:

X= -3

Step-by-step explanation:

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3 years ago

Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

zimovet [89]

Answer:

For every 2 boys in class, there is 1 girl in class

Step-by-step explanation:

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2 years ago

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bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago