Potassium-40 has a half life of 1.251×billion<span> years</span><span>. To determine the percentage potassium-40 remaining after 3.9 billion years, divide
3.9 by 1.251, = 3.12.
This is the number of times the original amount of potassium-40 reduces by 50%. The remaining percentage is therefore 100%/(3.12 * 2) = 16.03%.</span>
Answer:
The biggest advantage is that they have a higher resolution and are therefore also able of a higher magnification (up to 2 million times). Light microscopes can show a useful magnification only up to 1000-2000 times. This is a physical limit imposed by the wavelength of the light.
Explanation:
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Wave B because the compressions are more tightly packed, giving it a larger amplitude
Answer:
The "Jaws of Life" is a crucial tool to fire and rescue squads to save hundreds of lives every year. ... The “Jaws of Life” is used indeterminately for pretty much any type of heavy-duty tool that acts like a pair of scissors, cutter, spreader, or ram-device aimed at slicing and dicing through most automotive metals.
Explanation:
Answer:
a. S represents allele for short hair while s represents allele for long hair.
b. Ss (male) × ss (female)
c. 50% Ss, 50% ss
d. 3 long hair (ss), 3 short hair (Ss)
Explanation:
This question involves a single gene coding for hair length in guinea pigs. The allele for short hair (S) is dominant over the allele for long hair (s).
a. Letter "S" will represent the allele for short hair while letter "s" will represent the allele for long hair.
b. According to this question, a heterozygous male is crossed with a long-haired female. The genotype of the male guinea pig is "Ss" while that of the female is "ss". (see attachment for the punnet square)
c. The possible genotypes of the offsprings in this cross are: Ss and ss, each carrying 50% each as they are produced in a ½ Ss: ½ ss.
d. Since 50% of the offsprings will be both short haired and long haired, If they have six babies, 3 of them will be short-haired while 3 of them will also be long-haired.