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2 years ago

I need help on #19 and 20 please help !!!

Mathematics

1 answer:

tekilochka [14]2 years ago

3 0

-3x - 3y > 5
-3x + 3y - 3y > 3x + 5
-3y > 3x + 5
-3 -3
y < -x - 1²/₃

The answer is C.

y < |x + 4| + 2

The answer is B.

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Question 6

olga nikolaevna [1]

The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t

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2 years ago

A total of 50 raffle tickets are sold for a contest to win a car. If you purchase one ticket, what are your odds against winning

Darya [45]

Step-by-step explanation:

$odds \: against \: winning = \frac{1}{50} \\ \\$

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2 years ago

Veronica wants to buy a house that costs $249,900. She is going to make a 20% down payment. How

rosijanka [135]

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▹ Answer

▹ Step-by-Step Explanation

$\frac{20}{100} * $249,900 \\\\= $49,980$

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6 0

2 years ago

Read 2 more answers

If 10a+10b=35, what is the average (arithmetic mean) of a and b?

worty [1.4K]

Answer:

1.75

Step-by-step explanation:

If a and b are two numbers, then their arithmetic mean is

$\dfrac{a+b}{2}$

Given:

$10a+10b=35$

Divide this equation by 10:

$a+b=3.5$

Now, divide it by 2:

$\dfrac{a+b}{2}=\dfrac{3.5}{2}\\ \\\dfrac{a+b}{2}=1.75$

6 0

3 years ago

Find the oth term of the geometric sequence 7, 14, 28, ...

yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

$a_n=a_1\cdot r^{n-1}$

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

$\frac{14}{7}=2,\:\quad \frac{28}{14}=2$

The ratio of all the adjacent terms is the same and equal to

$r=2$

now substituting r = 2 and a₁ = 7 in the nth term

$a_n=a_1\cdot r^{n-1}$

$a_n=7\cdot \:2^{n-1}$

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

6 0

2 years ago