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Black_prince [1.1K]
3 years ago
8

Solve for m 8/k=n-3/m

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0
The answer is m=nk-3k/8
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What’s wants to. answer my question what is 123465839274+384x384729+384=? <br> (Email)
Sunny_sXe [5.5K]

Answer:

123613575594

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
The Value of x in the system of equation at the right is -2 what is the value of a? use elimination to help you find the value.
sammy [17]

2x-4y=-16
ax+4y=6      +
--------------------
2x+ax=-10;     for x=-2, 
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3
7 0
3 years ago
Evaluate the expression when x=3, y= -4, and z= -6 <br><br> xy<br> _<br> z
NeTakaya
The answer is probably 2 because if you plug in the numbers you would get 
3x-4=-12 divided by -6 = +2.
3 0
4 years ago
What can the intersection of a regular octagon and line segment be?
noname [10]

Answer:

See below

Step-by-step explanation:

Intersection of a regular octagon and a line segment can result in:

  • Triangle (ABC as example)
  • Quadrilateral (ABCD as example)
  • Pentagon (ABCDE as example)
  • Hexagon (ABCDEF as example)
  • Heptagon (ABCDEFG as example)

Refer to attached

8 0
3 years ago
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