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nikitadnepr [17]
3 years ago
10

"absmiddle" class="latex-formula">
how do I do this ​
Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

\sqrt[3]{6}≈1.817

Step-by-step explanation:

I used my calculator

type 3 and then \sqrt[x]{} 6

otez555 [7]3 years ago
3 0
In decimal form it is 1.8
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Seven subtracted from n is 18​
Vikentia [17]

Answer:

25

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Mercury is a naturally occurring metal that can be harmful to humans. The current recommendation is for humans to take in no mor
kirill [66]

Answer:

A.) A person weights 80 kg can consume Haddock fish = 149 grams

B.) A person weights 80 kg can consume Swordfish fish = 8 grams

C.) A person weights 80 kg can consume Tuna fish = 23 grams

D.) A person weights 80 kg can consume Snapper fish = 50 grams

Step-by-step explanation:

Given - Mercury is a naturally occurring metal that can be harmful to humans. The current recommendation is for humans to take in no more than 0.1 microgram for every kilogram of their weight per day. Fish generally carry high levels of mercury, although certain fish have higher mercury content than others. Fish, however, are healthy sources of many other nutrients, so nutritionists recommend keeping them in the human diet. The figure below shows the average mercury content of several types of fish.

To find - If a person weighs 82 kg, how much of each fish can they safely consume? round to the nearest gram.

A.Haddock

B.Swordfish

C.Tuna

D.Snapper​

Proof -

Firstly, determine how many micro grams of mercury a person can consume who weighs 82 kilograms.

⇒82 × 0.1 =  8.2 micro grams.

Now,

a.)

For Haddock fish-

It consumes 0.055 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.055

                                              = 149.09 ≈ 149 grams

So,

A person weights 80 kg can consume Haddock fish = 149 grams

b.)

For Swordfish fish-

It consumes 0.995 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.995

                                              = 8.24 ≈ 8 grams

So,

A person weights 80 kg can consume Swordfish fish = 8 grams

c.)

For Tuna fish-

It consumes 0.350 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.350

                                              = 23.43 ≈ 23 grams

So,

A person weights 80 kg can consume Tuna fish = 23 grams

d.)

For Snapper fish-

It consumes 0.165 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.165

                                              = 49.697 ≈ 50 grams

So,

A person weights 80 kg can consume Snapper fish = 50 grams

6 0
3 years ago
47 in = ? ft ? in<br><br> 3 ft 11 in<br><br> 4 ft 0 in<br><br> 3 ft 9 in<br><br> 564 ft 0 in
Veseljchak [2.6K]

Answer:

3ft 11 in

Step-by-step explanation:

1 foot equals 12 inches, 12 × 3 = 36 = 3 feet + 11 inches = 47 inches = 3ft 11in

8 0
3 years ago
In a group of 120 recruits at the police academy 80 are college graduates and 25 are army veterans. If 15 of the recruits are bo
Gre4nikov [31]

Answer:

the number of recruits neither be college graduate and nor army veterans is 30

Step-by-step explanation:

The computation of the number of recruits neither be college graduate and nor army veterans is as follows;

= Total recruits - (college students + army veterans - both college graduates & army veterans)

= 120 recruits - (80 + 25 - 15)

= 120 recruits - 90  

= 30

hence, the number of recruits neither be college graduate and nor army veterans is 30

4 0
3 years ago
Aaron was offered a job that paid a salary of \$57,000$57,000 in its first year. The salary was set to increase by 1% per year e
Jobisdone [24]

Answer:

The total amount received is: $1906650

Step-by-step explanation:

Given

a = \$57000 --- initial

b = 1\% --- rate

n = 29 --- time

Required

Determine the total amount at the end of 29 years

The given question is an illustration of geometric progression, and we are to solve for the sum of the first n terms

Where n = 29

r = 1 + b

r = 1 + 1\%

Express percentage as decimal

r = 1 + 0.01

r = 1.01

The required is the calculated using:

S_n = \frac{a(r^n - 1)}{r - 1}

So, we have:

S_n = \frac{57000 * (1.01^{29} - 1)}{1.01 - 1}

S_n = \frac{57000 * (1.3345- 1)}{0.01}

S_n = \frac{57000 * 0.3345}{0.01}

S_n = \frac{19066.5}{0.01}

S_n = 1906650

<em>The total amount received is: $1906650</em>

8 0
3 years ago
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