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saveliy_v [14]
2 years ago
10

An athlete has 75% of winning the race if he is not injured. If he is injured, his probability of winning the race is only 15%.

If the total chances of winning is 51%, what is the probability that he gets injured?
Mathematics
1 answer:
alekssr [168]2 years ago
8 0

Answer:

X = 'is the athlete injured' (X in {0,1})

Y = 'the athlete wins' (Y in {0,1})

P(Y=1|X=0) = 0.75

P(Y=1|X=1) = 0.15

P(Y=1) = 0.51

We are looking for P(X=1) - P(Y=1) = P(Y=1|X=0)*(1-P(X=1)) + P(Y=1|X=1)*P(X=1)

The above equation should provide you with the answer 0.4!

Step-by-step explanation:

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Help pls :(<br><br><br> Solve for x.<br> -4 + 3x = 20
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\huge\text{Hey there!}

\large\textsf{-4 + 3x = 20}\\\rightarrow\large\textsf{3x - 4 = 20}\\\\\large\text{ADD 4 to BOTH SIDES}\\\large\textsf{3x - 4 + 4 = 20 + 4}\\\large\text{CANCEL out: \textsf{-4 + 4} because that gives you \textsf 0}\\\large\text{KEEP: \textsf{20 + 4}} \text{ because it gives you the \textsf{x-value}}}\\\\\large\textsf{20 + 4 = \bf 24}\\\\\large\text{DIVIDE 3 to BOTH SIDES}\\\\\mathsf{\dfrac{3x}{3}= \dfrac{24}{3}}\\\large\text{CANCEL out: }\mathsf{\dfrac{3}{3}}\large\text{ because that gives you \textsf 1}

\large\text{KEEP: }\mathsf{\dfrac{24}{3}}\large\text{ because it helps gives you the result of the  \textsf{x-value}}\\\\\mathsf{x = \dfrac{24}{3}}\\\\\large\textsf{x= 24}\div \large\textsf{3}}\\\large\textsf{x = \bf 8}\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 8}}}}\huge\checkmark

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Me podrían ayudar a contestar estas preguntas, por favorspeak spanish
lisabon 2012 [21]

En un parallelogramo, los lados opuestos son paralelos. De la misma forma, los angulos opuestos son iguales y los angulos adjacentes suman 180 grados.

Con ello, podemos decir que:

a. Los lados RS y UT son paralelos.

b. Los lados RU y ST son paralelos.

c. El angulo en U es igual al angulo en S pues son opuestos

d. Los angulos en S y T son adjacentes . Esto quiere decir que, su suma es igual a 180 grados.

e. El angulo en R es igual al angulo en T pues son opuestos.

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Send it quick guys...
Paladinen [302]

Answer:

194

Step-by-step explanation:

Recall 2 rules to solve this easily:

1. (a+b)^2=a^2+2ab+b^2

2. (a-b)^2=a^2-2ab+b^2

<em>Now, if we let a = 7  and  b=4\sqrt{3}, we can say the problem is basically of the form:</em>

(a+b)^2 + (a-b)^2

This can be simplified using the rules:

(a+b)^2 + (a-b)^2\\a^2+2ab+b^2+a^2-2ab+b^2\\2a^2+2b^2

Now we can plug the values of a and b we initially thought of (remember though  \sqrt{x} \sqrt{x} =x):

2a^2+2b^2\\2(7)^2+2(4\sqrt{3})^2\\ 2(49)+2(4\sqrt{3})(4\sqrt{3})\\98+2(4)(4)(\sqrt{3} )(\sqrt{3} )\\98+2(4)(4)(3)\\98+96 \\194

194 is the final answer.

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