Answer:
πr²= 12.56
r²=12.56/3.14 = 4
r= 2
therefore , diameter = 2r = 2×2= 4 mm
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
My guess is 21
Step-by-step explanation:
A) blue/total = (3+2)/(8+2) = 5/10 = 50%
b) blue/total = (3)/(8 +2) = 3/10 = 30%
4 1/3 cup of flour = 2 3/4 cup of sugar
1 cup of flour = 2 3/4 ÷ 4 1/3 = 33/52 cup of sugar <=== answer
