Question

PLZ HELP ME, TY! Have a great day! WILL MARK BRAINLIEST! I need help can someone explain?

Answer 1

The equation of the line parallel to 8x – 16y = –14 and passes through (3, 0) is $y=\frac{1}{2}x-\frac{3}{2}$.

Solution:

Parallel line:

8x – 16y = –14

Subtract 8x on both sides,

–16y = –8x – 14

Divide by –16 on both sides, we get

$y=\frac{8}{16}x+\frac{14}{16}$

$m_1=\frac{8}{16}$

Slope of this line is $\frac{8}{16}$.

Slopes of the parallel lines are equal.

$m_1=m_2$

$m_2=\frac{8}{16}$

The line passes through the point (3, 0).

$x_1=3, y_1=0$

Point-slope formula:

$y-y_1=m(x-x_1)$

$y-0=\frac{8}{16} (x-3)$

$y=\frac{8}{16}x-\frac{24}{16}$

$y=\frac{1}{2}x-\frac{3}{2}$

The equation of the line parallel to 8x – 16y = –14 and passes through (3, 0) is $y=\frac{1}{2}x-\frac{3}{2}$.