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earnstyle [38]
3 years ago
13

In the diagram, PQ and ST are parallel lines. Find the value of x.please help!!​

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

x = 95°

Step-by-step explanation:

m\angle Q = 360\degree - 235\degree = 125\degree \\

Produce QR In such a way that it intersects ray ST at any point say M.

PQ || ST... (given) and Seg QM is transversal.

\therefore m\angle PQM + m\angle SMQ = 180\degree \\(interior \: \angle \:Postulate) \\\therefore 125\degree + m\angle SMQ = 180\degree \\\therefore m\angle SMQ = 180\degree -125\degree \\\therefore m\angle SMQ = 55\degree \\In\: \triangle SMR, \: x \: is \:exterior \: \angle \\\therefore x = 40\degree + 55\degree \\\huge \purple {\boxed {\therefore x = 95\degree}}

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What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Can someone help me with this?
deff fn [24]

Answer:

the answer is 200

Step-by-step explanation:

4 0
3 years ago
I need help on this please help!
Licemer1 [7]

Answer:

(b)0.56

(c)0.38

Step-by-step explanation:

(a)

P(Ben Pass) =0.8

Therefore: P(Ben fails)=1-0.8 =0.2

P(Tom Pass) =0.7

Therefore: P(Tom fails)=1-0.7 =0.3

See attached for the completed tree diagram

(b)Probability that both will pass

P(both will pass)=P(Ben pass and Tom pass)

=P(Ben pass) X P(Tom pass)

=0.8 X 0.7

=0.56

(c)The probability that only one of them will pass

Since either Tom or Ben can pass, we have:

P(only one of them will pass)

=P(Ben pass and Tom fails OR Ben Fails and Tom Pass)

=P(Ben pass and Tom fails)+P(Ben Fails and Tom Pass)

=(0.8 X 0.3) + (0.2 X 0.7)

=0.24 + 0.14

=0.38

8 0
3 years ago
Help please!!!!ASAP! Ill give brainliest! And 50pts!<br><br> What is the value of q?
fomenos
It is c hope this helps :)
4 0
3 years ago
Read 2 more answers
Tc = fixed cost + variable cost
natima [27]

Answer:

These correspond to two types of cost: fixed cost and variable cost. Fixed cost (FC): the cost of all fixed inputs in a production process. Another way of saying this: production costs that do not change with the quantity of output produced. Variable cost (VC): the cost of all variable inputs in a production process.

4 0
3 years ago
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