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uranmaximum [27]
3 years ago
7

In an experimental study on friendliness and tipping, every alternate customer to whom the waiter is extra friendly toward are r

eferred to as the...A. Control group
B. Experimental group
C. Nonexperimental group
D. Dependent group
Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

A. Control group  

Step-by-step explanation:

A control group is a group in an experiment or study that does not receive experimental procedure during such that it is then used as a benchmark to measure how the other tested subjects do.

An experimental group is a group in an experiment or study that receives an experimental procedure. The values of gotten from the test are recorded and the effect of independent variables on the dependent variables are determined.

Control experiment can be used to determine whether or not the customers are friendly. Experimental group will be the customers whom the waiter is extra friendly toward. The control group will be the alternate customer whom the waiter is not extra friendly toward.          

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Work out the values of a to e please
baherus [9]

Answer:

Step-by-step explanation:

a=10   (4,0,2,4,3,1,2,3,1,4)

b=4    (7,5,6,9)

c=6    (13,13,13,10,13,12)

d= 5   (17,16,17,17,16)

e=6    (21,23,20,20,21,23)

8 0
3 years ago
a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is
irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer


4 0
2 years ago
Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan
Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

0.3917 = 39.17% probability that she had found someone to help

4 0
3 years ago
PLEASE HELP ME !!! ASAP PLS!!!
tensa zangetsu [6.8K]

Answer:

AI and AJ

Step-by-step explanation:

Opposite rays start at the same point (A) and go in the complete opposite direction

8 0
3 years ago
Read 2 more answers
Are integers irrational
AVprozaik [17]
Well, some integers can be irrational, but not all! :) 
3 0
3 years ago
Read 2 more answers
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