To factor it completely you first look at the first term, if the a term is 1 then your good if it is not you need to divide it by whatever number to make the a term 1, in the first question the a term is just x^2 so it's good. Then,you focus on the b and c term, you have to find multiples of term C that adds up to term b. Going back to problem 1, c is 16 and b is 10. So the two factors would be 8 and 2,because 8×2=16 and 8+2=10. the final step is to put into the proper format,
(x+2) (x+3), which would be considered completely factored.
Step-by-step explanation:
Given
25 - (- 4)
= 25 + 4
= 29
Hope it will help :)
Step-by-step explanation:
![\sqrt{(x + 6) ^{2} } = \sqrt{18} \\ x + 6 = + - \sqrt{18} \\ x + 6 = + - \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28x%20%2B%206%29%20%5E%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B18%7D%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%7B18%7D%20%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%5B3%5D%7B2%7D%20)
4 rows because 4 times 8 equals 32, so then there are only 32 singers left. 64-32=32, and once again 4 times 8 equals 32.
Uh I’m not even gonna question it but thanks for the free points ig? Lol
