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julia-pushkina [17]
3 years ago
9

An item is regularly priced at $65. Laura bought it at a discount of 15% off the regular price. How much did Laura pay?

Mathematics
1 answer:
Sonja [21]3 years ago
7 0

Answer:

9.75

Step-by-step explanation:

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An airline charges 150 for a ticket and 20 for each bag.
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it will be C

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C = 20b + 150

Step-by-step explanation:

because it's 150 for a ticket for each 20 bags. depending on how many bags there are, it wi give you the answer of the cost.

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Roger has 47 cars. Can he group the cars in more than 2 ways?
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Yes he can, he could do:

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Combine like terms:
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3 years ago
What is -five sixths time six fifths
s2008m [1.1K]

Answer:

-five sixths= -5/6

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8 0
3 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
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