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hoa [83]
2 years ago
14

A digital scale measures weight to the nearest 0.2 pound. Which

Mathematics
1 answer:
AnnyKZ [126]2 years ago
4 0

Answer:

A

Step-by-step explanation:

This option contains a number that would appear on this scale.

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A rocket moves through outer space at 10,500 m/s. At this rate how much time would be required to travel the distance from Earth
Orlov [11]

Answer:

The answer is around 27.63 seconds.

Step-by-step explanation:

1 km equals 1000 meters so we have to multiply 10,500 and 1,000 which would equal 10,500,000 km. 10,500,000 divided by 380,000 which is around 27.63 seconds.

8 0
3 years ago
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Which equation shows y=34x−52y=34x−52 in standard form?
Nonamiya [84]
<span>y=34x−52
34x - y - 52 = 0</span>
3 0
3 years ago
Help me fast plzzzzzzzzzzz
mario62 [17]

this question is incorrect because the decimal quantity functional persistent shouldnt be in a sequential farfictional order so the answer would be that satisfactory angle of theslop devided by pi and then multiplied by the persistent. hope this helped!

5 0
2 years ago
Express the volume of the box as a<br>polynomial in the variable x
Whitepunk [10]

The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

<h3>How to determine the volume?</h3>

The complete question is added as an attachment

From the attached image, we have:

Length = 12 - 2x

Width = 7 - 2x

Height = x

The volume is calculated as:

Volume = Length * Width * Height

Substitute the known values in the above equation

Volume = (12 - 2x) * (7 - 2x) * x

This gives

Volume = x(12 - 2x)(7 - 2x)

Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

Read more about polynomial at:

brainly.com/question/4142886

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7 0
1 year ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
1 year ago
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