Let x and y represent the two angles.
.. x + y = 90 . . . . . . two angles are complementary
.. x -2y = 15 . . . . . . one angle is 15 more than twice the other (y = smaller angle)
Subtract the second equation from the first.
.. (x +y) -(x -2y) = (90) -(15)
.. 3y = 75
.. y = 25
The smaller angle is 25 degrees.
I think the answer would be 0.16
b.
Bedroom area
Lenght = 5 squares
= 5 × 1/4 inchi
= 5/4 inchi
Width = 4 squares
= 4 × 1/4 inchi
= 1 inchi
Large area = 5/4 × 1 inchi
= 5/4 inchi
Living room
Lenght = 7 squares
= 7 × 1/4 inchi
= 7/4 inchi
Width = 4 squares
= 4 × 1/4 inchi
= 1 inchi
Large area = 7/4 × 1 inchi
= 7/4 inchi
Total Area
Bedroom area + Living room area
= 5/4 + 7/4
= (5+7)/4 inchi
= 12/4 inchi
= 3 inchi
1 square yard = 1296 square inches
so 1 square inches = 1/1296 square yard
3 inchi = 3×1/1296
= 3/1296
= 1/432
Cost = 1/432 × $18
= $1/24
It would cost $1/24 to carpet the bedroom and living room.
Its either rational or not a real number but i think its not a real nmber
Answer:
Step-by-step explanation:
Domain:
![\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{3y-x}=\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{-(x-3y)}\\\\=\dfrac{x^2+9y^2}{x-3y}-\dfrac{6xy}{x-3y}=\dfrac{x^2+9y^2-6xy}{x-3y}\\\\=\dfrac{x^2-2(x)(3y)+(3y)^2}{3y-x}=\dfrac{(x-3y)^2}{3y-x}\\\\=\dfrac{\bigg[-1(3y-x)\bigg]^2}{3y-x}=\dfrac{(-1)^2(3y-x)^2}{3y-x}\\\\=\dfrac{1(x-3y)(x-3y)}{x-3y}=x-3y](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D%2B%5Cdfrac%7B6xy%7D%7B3y-x%7D%3D%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D%2B%5Cdfrac%7B6xy%7D%7B-%28x-3y%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D-%5Cdfrac%7B6xy%7D%7Bx-3y%7D%3D%5Cdfrac%7Bx%5E2%2B9y%5E2-6xy%7D%7Bx-3y%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bx%5E2-2%28x%29%283y%29%2B%283y%29%5E2%7D%7B3y-x%7D%3D%5Cdfrac%7B%28x-3y%29%5E2%7D%7B3y-x%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Cbigg%5B-1%283y-x%29%5Cbigg%5D%5E2%7D%7B3y-x%7D%3D%5Cdfrac%7B%28-1%29%5E2%283y-x%29%5E2%7D%7B3y-x%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%28x-3y%29%28x-3y%29%7D%7Bx-3y%7D%3Dx-3y)
Used:
The distributive property: a(b + c) = ab + ac
(a - b)² = a² - 2ab + b²
