If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
Answer: u= 3.2
Step-by-step explanation:
divide both by 4
![x= \sqrt[8]{y} \\ y = z^{16} ](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B8%5D%7By%7D%0A%5C%5C%20y%20%3D%20z%5E%7B16%7D%0A%0A%20)
Plug "y" into the first equation.
![x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B8%5D%7Bz%5E%7B16%7D%7D%20%3D%20%28z%5E%7B16%7D%29%5E%7B1%2F8%7D%20%3D%20z%5E%7B16%2F8%7D%20%3D%20z%5E2)
Answer:
the volume is about 1884
Step-by-step explanation:
v of cone= 1/3(pi)r^2h
diameter to radius is 30=5.477225575051661
so 1/3(3.14)5.477225575051661^2(60)
=1/3(3.14)30(60)
=1/3(5652)
=1884
hope this helps
