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MrRa [10]
4 years ago
10

Fill.I’m the missing number equation for the table

Mathematics
1 answer:
Virty [35]4 years ago
7 0

Answer:

for every 1 hour, its 5 dollars

Step-by-step explanation:

You might be interested in
235*45 please help me
harkovskaia [24]
235 x 40 = 9400
235 x 5 = 1175

9400 + 1175 = 10575

235 x 45 = 10575
3 0
3 years ago
Help me plz check it
Nikolay [14]

3 1/4 = 3.25

1 mile = 5280

5280 * 3.25 = 17,160

Correct answer is D. 17,160

6 0
3 years ago
When the light turns yellow, should you stop or go through it? An article defines the “indecision zone” as the period when a veh
olga2289 [7]

Answer:

Probability:  0.7190

There is not enough evidence at the 5% level of significance to suggest that there is difference in proportions of red-light runners between the two intersections

Step-by-step explanation:

We can conduct a hypothesis test for the difference of 2 proportions. If there is no difference in proportion of red-light runners between the 2 lights, then the difference in proportions will be zero. That makes the null hypothesis

H0: p1 - p2 = 0

The question is asking whether there is a difference, meaning that the difference can be higher or lower.  If there is a difference, the proportions are not equal. This makes the alternate hypothesis

Ha: p1 - p2 ≠ 0

This is a two tailed test  

We will use a significance level of 95% to conduct our test. This makes the critical values for our test statistic: z > 1.96 or z < -1.96.  

If our test statistic falls in either region, we will reject the null hypothesis.

See the attached photo for the hypothesis and conclusion

The z-value of the test statistic is z = 0.58.  

P(z < 0.58) = 0.7190

8 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
sladkih [1.3K]

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

               =0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

4 0
4 years ago
PLEASE ANSWER FAST
s2008m [1.1K]

Answer:

22 November

Step-by-step explanation:

First we have to find the total length she swims in 1 day

= 2(length of the swimming pool) x no. of lengths she swims in 1 day

=2x30x20

=120m she covers in 1 day

10km = 10,000m

no of days= total distance/ distance she covers in 1 day

=10000/120

=83.3 days

5 0
3 years ago
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