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Anestetic [448]
3 years ago
6

PLEASE ANSWER FAST

Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

22 November

Step-by-step explanation:

First we have to find the total length she swims in 1 day

= 2(length of the swimming pool) x no. of lengths she swims in 1 day

=2x30x20

=120m she covers in 1 day

10km = 10,000m

no of days= total distance/ distance she covers in 1 day

=10000/120

=83.3 days

You might be interested in
-84(-3 - 5p)=-176 help please
vagabundo [1.1K]
-84 = 3(5n + 2)
 
Multiply everything in the parenthesis.

-84 = 3(5n + 2)
          3*5n + 3*2

-84 = 15n + 6 
Subtract 6 from both sides

-84 = 15n + 6 
-6                -6

-90 = 15n
Divide 15 from both sides

-90 = 15n
--------------
15       15

-6 = n

-6 is your answer.
5 0
3 years ago
Read 2 more answers
What the answer plz help fast? If you get it right i will mark you brainless ❤️
romanna [79]

Answer:

You'll mark me brainless?! I shouldn't answer corectly then XD

The answer (keep in mind that i'm answering incorrectly) A, or B, or D, or E.

Do you see what I did there ;)

Step-by-step explanation:

May I have brainliest please :)

3 0
3 years ago
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2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2<br> uh hi how do you cope with a p/r/nt h/tt/ng you? -Regina
Llana [10]

2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2 =  - 30

4 0
3 years ago
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A batch of cookies calls for 3/4 cup of flour. You want to make 1/2 of a batch.
kipiarov [429]
Here you goooooooooo

8 0
3 years ago
An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 140 students in th
Arlecino [84]

Answer:

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

140 students, so n = 140

B or better are grades of A or B.

5% earn As, 23% earn Bs, so p = 0.05 + 0.23 = 0.28

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.2056

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.3544

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

7 0
3 years ago
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