The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
Answer:
c. y + 3 = (1/2)(x - 1)
Step-by-step explanation:
Step-by-step explanation:
3(x+1)=-2(x-1)-4
3x+3=-2x+2-4
by combining like terms on one side and unlike term by other side
3x+2x=2-4-3
5x= -5
x= -5/5
x=-1
6 11/14 would be the correct answer to your math problem!
