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Elanso [62]
3 years ago
13

Write an equation in slope-intercept form for the line that passes through (-3,2) and is perpendicular to the line y=3/2+4

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer: the equation is slope-intercept form y = -2/3x




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Last year, a large trucking company delivered 5.5x10^5 tons of goods with an average value of $23,000 per ton. What was the tota
AleksandrR [38]
The total value is:
5. 5 x 10 ^5 * 23 x 10^3 = 
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4 0
3 years ago
X = 3y - 6 2x - 4y = 8 Solve the system of equations using substitution.
Brut [27]
Hello

x = 3y - 6
2x - 4y = 8
We need to start by solving 3y - 6 for x
Substitute 3y -6 for x in 2x
2x - 4y = 8
2(3y - 6) - 4y = 8
2y - 12 = 8
2y = 8 + 12
2y = 20
Divide both sides by 2
2y/2 = 20/2
y = 10

Now, substitute 10 for y in x= 3y
x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x= 24

Answer : x = 24 and y=10

I hope this help!
7 0
3 years ago
Read 2 more answers
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
The amount Cami raised during last year’s charity walk, $45.50, is StartFraction 7 over 10 EndFraction of the amount she raised
barxatty [35]

Answer:

The equation is given by:

n = \frac{7}{10} \times 45.50

Step-by-step explanation:

During last years's charity walk, she raised $45.50.

During this years walk, she raised n, which is 7/10 of this amount. So, the equation is given by:

n = \frac{7}{10} \times 45.50

3 0
3 years ago
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