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Elanso [62]
3 years ago
13

Write an equation in slope-intercept form for the line that passes through (-3,2) and is perpendicular to the line y=3/2+4

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer: the equation is slope-intercept form y = -2/3x




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35 points in 20 minutes or 49 points in 35 minutes? Find which is greater.
Vitek1552 [10]

Answer:

35 points in 20minutes is greater than 49 points in 35 minutes.

7 0
3 years ago
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If x-13 = k and k = 3, what is the value of x?
77julia77 [94]

Answer:

x = 16

16 - 13 = 3

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Step-by-step explanation:

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3 years ago
Find the derivative of f(x)=x+1/x-1 using first principal​
zepelin [54]

f ' ( x ) = 1 ( x + 1 ) 2

 

Explanation:

differentiating from first principles

f ' ( x ) = lim h → 0

 

f ( x + h ) − f ( x ) h

f ' ( x ) = lim h → 0

 x + h x + h + 1 − x x + 1 h

the aim now is to eliminate h from the denominator

f ' ( x ) = lim h =0  

( x + h ) ( x + 1 )− x ( x + h + 1) h ( x + 1 ) ( x + h + 1 )

f ' ( x ) = lim h → 0

 x 2 + h x + x + h − x 2 − h x − x h ( x + 1 ) ( x+h + 1 )

f ' ( x ) = lim h → 0

 

h 1 h 1 ( x + 1 ) ( x + h +1 )

f ' ( x ) = 1 ( x + 1 ) 2

5 0
3 years ago
4. See if you can find "like-terms" in the expression and
WITCHER [35]

Answer:

After finding like terms and solving, we get \mathbf{3x^2+3x+16}

Step-by-step explanation:

We need to find like terms and simplify the expression 4- 2x + x^2 + 5x + 12 + 2x^2

Like terms: The terms who have same variable and exponent are called like terms.

So, Combining like terms and solving:

4- 2x + x^2 + 5x + 12 + 2x^2\\=4+12-2x+5x+x^2+2x^2\\Now \ solving:\\=16+3x+3x^2\\Rearranging \ the \ terms:\\=3x^2+3x+16

So, after finding like terms and solving, we get \mathbf{3x^2+3x+16}

<u><em>Note: In the question given we have - and + sign with the term 5x</em></u> i.e 4- 2x + x^2 -+ 5x + 12 + 2x^2

I have solved using +5x, but if the term is -5x then the solution will be:

4- 2x + x^2 - 5x + 12 + 2x^2\\=4+12-2x-5x+x^2+2x^2\\Now \ solving:\\=16-7x+3x^2\\Rearranging \ the \ terms:\\=3x^2-7x+16

So, the answer will be: \mathbf{3x^2-7x+16}

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3 years ago
Later, the clowns transform rectangle JKMN into a congruent image with the vertices
Andre45 [30]
K would be the 180 anti clock and up to
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