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nydimaria [60]
3 years ago
7

What is the product? (2x-1)(x+4) 2x²-4 0 2x²+4 0 2x² + 7x-4 2x² – 7x-4

Mathematics
2 answers:
blondinia [14]3 years ago
8 0

Answer:2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4) multiply (2x by x and 4 also -1 by x and 4)

2x^2 +8x -X-4 (combine like terms (8x-x) )

2x^2+7x-4. (Answer)

vladimir2022 [97]3 years ago
3 0

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

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If SU and VX are parallel lines and mUTW = 131°, what is mVWT?
TiliK225 [7]

<u>Answer:</u>

∠VWT = 131°

<u>Explanation:</u>

∠VWT is equal to ∠UTW because they are Alternate inner angles. Since they are equal, we know that the measure of ∠VWT is 131°.

Hoped this helped!

4 0
3 years ago
Matthew makes 5 apple pies for every 3 blueberry pies last week Matthew made 15 blueberry pies how many apple pies did he make
KIM [24]

Answer:

25

Step-by-step explanation:

5:3

3*5=15

This means that 5 apple pies times 5.

5*5=25

<u>25</u>:15

3 0
4 years ago
We will use the values off(x) at the points 0.0,0.2,0.4,0.6,0.8. Generate the data set beforeyou start the numerical integration
leva [86]

Answer:

Check attachment for complete question and answer

8 0
3 years ago
If there are 15 students who don’t wear glasses, how many students are in the class?
mixer [17]
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4 0
3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
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