Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
The slope-intercept form:
y = mx + b
m - slope
b - y-intercept
We have m = 3 and b = -3. Substitute:
<h3>y = 3x - 3</h3>
10=1+9 1x9=9
=2+8 2x8=16
=3+7 3x7=21
=4+6 4x6=24
=5+5 5x5=25
↑ Left: the possible measurements of the two fences, Right: the possible areas
out of the areas calculated, 25 sq feet is the maximum. :)
Ans: 25 square feet
