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DochEvi [55]
3 years ago
12

Andy, taylor and ben share in the teams payments in the ratio 1:3:4 what percentage does andy get

Mathematics
1 answer:
natita [175]3 years ago
5 0
Andy gets 12.5% if the payment
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Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

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3 years ago
206 - Straight lines graph 1 what are the answers?
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Answer:

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Step-by-step explanation:

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Geometry - Law of Sines question #17. Please help, I am stuck.
Flauer [41]

By the law of sines, m∠<em>EFG</em> is such that

sin(m∠<em>EFG</em>) / (8 in.) = sin(m∠<em>G</em>) / (7.5 in)

so you need to find m∠<em>G</em>.

The interior angles to any triangle sum to 180°, so

m∠<em>DEG</em> = m∠<em>D</em> + m∠<em>G</em> + 43°

m∠<em>DEG</em> + m∠<em>D</em> + m∠<em>G </em>= 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

180° = 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

137° = 2 (m∠<em>D</em> + m∠<em>G</em>)

68.5° = m∠<em>D</em> + m∠<em>G</em>

But ∆<em>DEG</em> is isosceles, so m∠<em>D</em> = m∠<em>G</em>, which means

68.5° = 2 m∠<em>G</em>

34.25° = m∠<em>G</em>

<em />

Then

sin(m∠<em>EFG</em>) = (8 in.) sin(34.25°) / (7.5 in)

m∠<em>EFG</em> ≈ sin⁻¹(0.600325) ≈ 36.8932°

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I need help with this problem
zhuklara [117]

Answer:

easy so first 190-15=175  175 lbs. is the light heavyweight class weight limit

Step-by-step explanation:

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Could someone Help it’s a new topic
bagirrra123 [75]

Answer:

So to do this you need a protactor and measure it with it, then add the total

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