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Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has

Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {

// declaration and initialization of integer variables

int k, memberID = 12, nMembers=5;

bool isAMember;

// declaration and initialization of integer array

int currentMembers[] = {12, 34, 56, 78, 90};

for(k=0; k<nMembers; k++)

{

if(memberID == currentMembers[k])

{

// when member is found in the array, the loop is exited using break

isAMember = true;

break;

}

else

isAMember = false;

}

return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

{

if(memberID == currentMembers[k])

{

isAMember = true;

break;

}

else

isAMember = false;

}

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

4 0

3 years ago

As you are talking to your colleague over the phone, the sound of an airplane flying low drowns out part of your conversation. I

Rasek [7]

Answer:

Interference.

Explanation:

As the user is communicating with their friend through the mobile, most of their interaction is interrupted by the noise of an airplane flying at low hight. Instantly afterward, the user's mobile phone rang, disrupting the communication once more.

So, according to the following scenario both of those are examples of interference.

6 0

3 years ago

I really need the answer now!!

guajiro [1.7K]

Answer:

3. B.

4. B.

5. B.

6. C.

7. D.

8. C.

9. C.

10. D.

Explanation:

I hope I helped you.

4 0

2 years ago

What is input process<br>

riadik2000 [5.3K]

Answer:

describing the structure of an information processing program or another process. Many introductory programming and systems analysis texts introduce this as the most basic structure for describing a process.

Explanation:

A requirement from the environment (input)

A computation based on the requirement (process)

A provision for the environment (output)

Example: A small engineering firm believes there are problems with its hiring process. Several of the junior engineers that have been hired remained at the firm for less than one year. This is a considerable cost to the firm, since recruiting and training new engineers is time consuming and expensive. The human resources manager decides to put together a group of people with extensive experience hiring new engineers. One of their first tasks is to produce an input-output model of the hiring process. They generate the following.

4 0

3 years ago

Building a String Library

maw [93]

Code:

def myAppend( str, ch ):
# Return a new string that is like str but with
# character ch added at the end
return str + ch

def myCount( str, ch ):
# Return the number of times character ch appears
# in str.

# initiaalizing count with 0
count = 0

# iterating over every characters present in str
for character in str:
# incrementing count by 1 if character == ch
if character == ch:
count += 1

# returning count
return count

def myExtend( str1, str2 ):
# Return a new string that contains the elements of
# str1 followed by the elements of str2, in the same
# order they appear in str2.

# concatenating both strings and returning its result
return str1 + str2

def myMin( str ):
# Return the character in str with the lowest ASCII code.

# If str is empty, print "Empty string: no min value"
# and return None.
if str == "":
print("Empty string: no min value")
return None

# storing first character from str in char
char = str[0]

# iterating over every characters present in str
for character in str:
# if current character is lower than char then
# assigning char with current character
if character < char:
char = character
# returning char
return char

def myInsert( str, i, ch ):
# Return a new string like str except that ch has been
# inserted at the ith position. I.e., the string is now
# one character longer than before.

# Print "Invalid index" if
# i is greater than the length of str and return None.

if i > len(str):
print("Invalid index")
return None

# str[:i] gives substring starting from 0 and upto ith position
# str[i:] gives substring starting from i and till last position
# returning the concatenated result of all three
return str[:i]+ch+str[i:]

def myPop( str, i ):
# Return two results:
# 1. a new string that is like str but with the ith
# element removed;
# 2. the value that was removed.
# Print "Invalid index" if i is greater than or
# equal to len(str), and return str unchanged and None
if i >= len(str):
print("Invalid index")
return str, None

# finding new string without ith character
new_str = str[:i] + str[i+1:]

# returning new_str and popped character
return new_str, str[i]

def myFind( str, ch ):
# Return the index of the first (leftmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str
for i in range(length):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1

def myRFind( str, ch ):
# Return the index of the last (rightmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str from right side
for i in range(length-1, 0, -1):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1

def myRemove( str, ch ):
# Return a new string with the first occurrence of ch
# removed. If there is none, return str.

# returning str if ch is not present in str
if ch not in str:
return str

# finding position of first occurence of ch in str
pos = 0

for char in str:
# stopping loop if both character matches
if char == ch:
break
# incrementing pos by 1
pos += 1

# returning strig excluding first occurence of ch
return str[:pos] + str[pos+1:]

def myRemoveAll( str, ch ):
# Return a new string with all occurrences of ch.
# removed. If there are none, return str.

# creating an empty string
string = ""

# iterating over each and every character of str
for char in str:
# if char is not matching with ch then adding it to string
if char!=ch:
string += char
# returning string
return string

def myReverse( str ):
# Return a new string like str but with the characters
# in the reverse order.

return str[::-1]

6 0

2 years ago