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Ilya [14]
3 years ago
5

What is the formula of area that has the side of 6 cm and the shape is a square

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

6^{2} or 6 * 6

Step-by-step explanation:

Since a square's sides are all equal to each other  you can use this formula for  finding the area of a rectangle which is Base x Height or since all the sides are equal to each other you can just square the one side to get the desired answer!

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The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

7 0
3 years ago
Read 2 more answers
Solve for x,W 3x+3W-66 (1) 7 12x+15W-300 (2)
Ksenya-84 [330]

Answer:

x=10 and W=12

Step-by-step explanation:

Let's solve the equations. First we need to understand that the problem can be solved because we have two variables (x, W) and two equations.

Now, we have the following equations:

3x+3W-66 making the equation equal to 0:

3x+3W-66=0 which can be express as:

3x=-3W+66

x=(-3W+66)/3

x=-W+22 (equation 1)

The next equation is:

12x+15W-300 making the equation equal to 0 and then divided by 3:

(12x+15W-300)/3=0 which is:

4x+5W-100=0 (equation 2), using equation 1 we can write:

4(-W+22)+5W-100=0

-4W+88+5W-100=0

W-12=0

W=12

Using W=12 in equation 2 we have:

4x+5W-100=0

4x+5*(12)-100=0

4x+(60)-100=0

4x-40=0

4x=40

x=40/4

x=10

In conclusion the solution for the equations are: x=10 and W=12.

3 0
3 years ago
Solve for x.<br> 3 + 9x = 11x - 7
-BARSIC- [3]

Answer:

3 + 9x = 11x - 7

simplify

9x + 3 = 11x - 7

subtract 11x from both sides

-11x             -11x

-2x + 3 = -7

get rid of constants first by subtracting by 3 from both sides

-3            -3

-2x = -10

divide both sides by -2 since that is the inverse operation of multiplication

/-2    /-2

X = 5

5 0
2 years ago
Read 2 more answers
Please show how the following equasion Square root of 64+6/-2*-2 I cannot arrive at the answer of 9.5
Delicious77 [7]

Answer:

9.5

Step-by-step explanation:

\sqrt{64}+\frac{6}{-2\left(-2\right)}

\sqrt{64}+\frac{6}{2 \times 2}

8+\frac{6}{4}

\frac{19}{2}

=9.5

7 0
3 years ago
Read 2 more answers
Solve the inequality. Enter any fractions as reduced improper fractions. 4x ≤ -2/5(6x + 6) The solution is _____​
Deffense [45]

Answer:

x≤ -3/8

Step-by-step explanation:

4x\le \:-\frac{2}{5}\left(6x+6\right)\\

Expand ;

\mathrm{Expand\:}-\frac{2}{5}\left(6x+6\right):\quad -\frac{12}{5}x-\frac{12}{5}

4x\le \:-\frac{12}{5}x-\frac{12}{5}\\\\\mathrm{Add\:}\frac{12}{5}x\mathrm{\:to\:both\:sides}\\\\4x+\frac{12}{5}x\le \:-\frac{12}{5}x-\frac{12}{5}+\frac{12}{5}x

Simplify

\frac{32}{5}x\le \:-\frac{12}{5}\\\\Multiply \:both\:sides\:by\:5\\5\times\frac{32}{5}x\le \:5\left(-\frac{12}{5}\right)\\\\Simplify\\32x\le \:-12\\\\Divide \:both\:sides\:by\:32\\\frac{32x}{32}\le \frac{-12}{32}\\\\Simplify\\x\le \:-\frac{3}{8}

6 0
3 years ago
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