The sum of 3 and 5 divided by z (numerical expression)

The tables represent the functions f(x) and g(x).

adell [148]

Answer:

Step-by-step explanation:

it's - 6 Anasta :)

4 0

2 years ago

The rectangle shown is dilated by a scale factor of 1/5

Harrizon [31]

Answer:

A'B'= 3 cm and B'D' = 1.6 cm

Step-by-step explanation:

First of all, we are told that the scale factor = 1/5

Now,we know that If the scale factor is less than 1, then the dilation is a reduction.

Thus, in this question the dilation is a reduction.

For us to calculate the dimensions of the dilated rectangle, we'll multiply the original dimensions by the scale factor

Thus;

A'B' = AB(1/5)

A'B' = 15(1/5) = 3 cm

B'D' = BD(1/5) = 8(1/5) = 1.6 cm

Thus, The length of each side of the dilated rectangle are;

A'B'= 3 cm and B'D' = 1.6 cm

5 0

3 years ago

A basketball team played six games. In those games, the team won by 8 points, lost by 25,won by 9, won by 10,lost by 1, and won

Aneli [31]

Answer:

about 10 without a remainder of 4

Step-by-step explanation:

So, add up the number and divide by how many number you have (definition of mean). 8 + 25 + 9 + 10 + 11 + 1 all divide by 6 (since there are 6 numbers)

8 + 25 + 9 + 10 + 11 + 1 is 64.

64/6 is about 10 without a remainder of 4

4 0

2 years ago

For Carolinas birthday her mom took her and 4 friends to a water park. Carolinas mom paid $40 for 5 student tickets.what was the

____ [38]

If you divide 40 and 5 it equals $8 for 1 student ticket

3 0

3 years ago

Read 2 more answers

A large cube has a volume of 1 cubic unit. A small cube has a volume of 1 27 of a cubic unit. What is the difference between the

ExtremeBDS [4]

Given:

Volume of Large cube = 1 cubic unit

Volume of small cube = $\dfrac{1}{27}$ cubic unit

To find:

The difference between the edge length of the large cube and the edge length of the small cube.

Solution:

Let the edges of large and small cubes are $a_1$ and $a_2$ respectively.

We know that, volume of a cube is

$V=(edge)^3$

Volume of Large cube = 1 cubic unit

$(a_1)^3=1$

Taking cube root on both sides, we get

$a_1=1$

So, edge of large cube is 1 unit.

Volume of small cube = $\dfrac{1}{27}$ cubic unit

$(a_2)^3=\dfrac{1}{27}$

Taking cube root on both sides, we get

$a_2=\dfrac{1}{3}$

So, edge of large cube is $\dfrac{1}{3}$ unit.

Now, difference between them is

$d=a_1-a-2$

$d=1-\dfrac{1}{3}$

$d=\dfrac{3-1}{3}$

$d=\dfrac{2}{3}$

Therefore, the difference between the edge length of the large cube and the edge length of the small cube is $\dfrac{2}{3}$ unit.

6 0

3 years ago