The sides
12-3a
12-3a
4(2a-5)=8a-40
so for perimeter we + them
(12-3a)+(12-3a)+(8a-40)
=
2a-16
The unit form for that is
5,500
<span>The arcs must intersect because the point at which the arcs intersect forms the halfway point of the angle; if they don’t intersect, the angle will not be bisected. </span>
Step-by-step explanation:

Step-by-step explanation:
Given :
Given that lines a and b are parallel, angles 1 and 5 are congruent because they are corresponding angles, and angles 1 and 4 are congruent because they are vertical angles
To find : by which property are angles 4 and 5 congruent
Solution :
We know that if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.
Also, we know that if two things are equal to the same thing then they are equal to each other . In this case, we can say that if two angles are congruent to a third angle, then they are congruent to each other. As angles 4 and 5 are both congruent to angle 1, they are congruent to each other but angles 4 and 5 are alternate interior angles. So, if parallel lines have a transversal, alternate interior angles are congruent.