Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
Answer:
A. Yes, the result is a binomial probability distribution.
Step-by-step explanation:
The experiment above depicts a binomial probability distribution because the 4 required conditions are met :
1.) The distribution is independent as the possible outcome of each trial is the same.
2.) There are two possible categories and the result of each trial is one of two outcomes : Yes or No
3.) The number of observation is fixed at sample size of 5500
4.) The probability of success and failure of each trial is the same for all trials in the sample.
Hence, we can conclude that the experiment depicts a binomial probability distribution.
Answer:
v > -25/p
r = -5 +7/3 w
Step-by-step explanation:
- pv + 40 < 65
Subtract 40 from each side
- pv + 40-40 < 65-40
-pv < 25
Divide each side by -p (remember to flip the inequality since we are dividing by a negative)
-pv/-p > 25/-p
v > -25/p
7w - 3r = 15
Subtract 7w from each side
7w-7w - 3r = 15-7w
-3r = 15-7w
Divide by -3
-3r/-3 = (15-7w)/-3
r = -5 +7/3 w
The answer is 2268pi ft^3
Answer: x^(2)-3x-28=0
Step-by-step explanation:
