V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
The expression is 2 x3 + 7 =13
In base 5 the place values (from right to left) are the ones place, the 5's place and the 25's place. The highest digit you can write in any column is a 4.
333 would be (3 x 25) + (3 x 5) + (3 x 1) which is 93 in base 10.
30 would be (3x5) + (0 x 1) which is 15 in base 10.
The sum of 93 and 15 is 108 in base 10.
Now lets write that in base 5 - We can have 4 25's so there will be a 4 in the 25's column. Since 4 x 25 = 100 we still have to account for 8 to get to 108.
We can have 1 five in the 5's columns since 1 x 5 is 5. Now we have 3 left over which we can place in the one's column
Final answer 333₅ + 30₅ = 413₅
Answer:
7
Step-by-step explanation:
6×4=24
52-24=28
28÷4=7
Answer:
see picture
Step-by-step explanation: