If I have a cylindrical shaped has container with a radius of 8 cm and a height of 20 cm. a) How many ounces of water would it t
1 answer:
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Answer:
D = 141
Step-by-step explanation:
The given quadratic equation is
.
It is required to find the value of the discriminant. The value of discriminant of any quadratic equation is given by :
Here, a = 5, b = 9 and c = -3
On plugging all the values, we get :
So, the value of discriminant for y is 141.
Answer:
Step-by-step explanation:
we want to figure out the general term of the following recurrence relation
we are given a linear homogeneous recurrence relation which degree is 2. In order to find the general term ,we need to make it a characteristic equation i.e
the steps for solving a linear homogeneous recurrence relation are as follows:
- Create the characteristic equation by moving every term to the left-hand side, set equal to zero.
- Solve the polynomial by factoring or the quadratic formula.
- Determine the form for each solution: distinct roots, repeated roots, or complex roots.
- Use initial conditions to find coefficients using systems of equations or matrices.
Step-1:Create the characteristic equation
Step-2:Solve the polynomial by factoring
factor the quadratic:
solve for x:
Step-3:Determine the form for each solution
since we've two distinct roots,we'd utilize the following formula:
so substitute the roots we got:
Step-4:Use initial conditions to find coefficients using systems of equations
create the system of equation:
solve the system of equation which yields:
finally substitute:
and we're done!
The volume of the prism is 144 ft^3. If we use the letter V to represent volume, the formula for the volume of a rectangular prism is V=length*width*height. When you plug in the numbers, the equation is V=12*6*2. When you multiply these three numbers together, you get 144. Because you are finding the volume, your units are cubed, so your answer is 144 ft^3. I have attached an image of this problem written out (I’m sorry if the image is bad, I drew it on my phone). If you need any more help or any clarification, please let me know and I will be happy to help!
