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4 years ago

Please help with this. Thanks

Mathematics

1 answer:

lisov135 [29]4 years ago

4 0

Answer:

$\sqrt{106}$

Step-by-step explanation:

Given <u>v</u> = < - 5, 9 > then the magnitude is

| <u>v</u> | = $\sqrt{(-5)^2+9^2}$ = $\sqrt{25+81}$ = $\sqrt{106}$

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Pls, help due in 10 mins! Pls, answer both questions!

vredina [299]

Answer:

Answer for first question is 22 yards!

Step-by-step explanation:

I used to do this, you have to multiply. A way of helping, is to split it in half, then add it all together. Now, I am not always accurate but I hope this helps you!

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3 years ago

the manager of a cafe bought hazelnut coffee beans for $7.00 per pound, and vanilla coffee beans for $4.00 per pound. she bought

Ann [662]

The answer is E because if you take 60 pounds of hazel nut coffee you spend 420$ and that would leave 30 pounds of vanilla left which equals 120$ and if you and those two numbers you get the sum of how much money she spent on coffee.

3 0

3 years ago

In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour

Lesechka [4]

Answer:

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=54$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=21$ represent the sample standard deviation

n=16 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Now we have everything in order to replace into formula (1):

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

4 0

3 years ago

A brother and a sister are in the same math class. there are 8 boys and 10 girls in the class. one boy and one girl are randomly

timama [110]

The best one is 1/9 maybe

5 0

3 years ago

Read 2 more answers

3. An electric bill is an essential expense for young people who get their first

Dmitrij [34]

Answer:

Mean = $123.8

Range= $72

Variance= $607.344

Standard deviation=$ 24.64

Step by step explanation:

The list of the data of electricity bill on ascending order

$88,$90,$90,$95,$110,$115,$120,$126,$144,$150

Mean = (summation of($88,$90,$90,$95,$110,$115,$120,$126,$144,$150))/10

Mean = 1238/10

Mean = $123.8

Range= highest value- Lowest VA

Range= 150-88

Range= $72

Variance=( (88-123.8)²+(90-123.8)²+(90-123.8)²+(95-123.8)²+(110-123.8)²+(115-123.8)²+(120-123.8)²+(126-123.8)²+(144-123.8)²+(150-123.8)²)/10

Variance= (1281.64+1142.44+1142.44+829.44+190.44+77.44+14.44+4.84+295.84+408.04+686.44)/10

Variance= 6073.44/10

Variance=$ 607.344

Standard deviation= √variance

Standard deviation= √ 607.344

Standard deviation=$ 24.64

6 0

3 years ago