The answer should be 1003.53
Answer:
i have the same question someone helppppppp
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
then f(x)=0 if x<0 and f(x)=x if x≥0.
When x→-∞, f is the constant function zero, therefore 
. When x→∞, f(x)=x and x grows indefinitely. Thus 
f is differentiable if x≠0. If x>0, f'(x)=1 (the derivative of f(x)=x) and if x<0, f'(0)=0 (the derivative of the constant zero). In x=0, the right-hand derivative is 1, but the left-hand derivative is 0, hence f'(0) does not exist,
f'(x)>0 for all x>0. Therefore f(x) is strictly increasing on the inverval (0,∞).
Answer:
The correct answer is c. f(x) = 1/(x + 4)
Step-by-step explanation:
We can tell this because as the bottom of the equation (x + 4) approaches 0, the equation gets larger and larger.
Also, you can note that -4 is a asymptote, which can only be from the bottom of the equation being equal to 0. This is only true in option c.
First find the LCD of the denominators then convert the fractions. Then you can subtract.
for example
2/7 - 1/4
LCD of 4 and 7 is 28 so we convert to fractions with denominator 28
1/4 = 1*7 / 4*7 = 7 /28
2/7 = 2*4 / 7*4 = 8/28
so 2/7 - 1/4 = 8 /28 / 7/28 = 1/28 answer
