Example:
1. 2/3,3/4
<span>2. 3/5,1/2 </span>
<span>3. 2/5,1/3 </span>
<span>4. 5.6,4.5 </span>
<span>5. 1/2,2/3 </span>
<span>6. 3/7,2/3 </span>
<span>7. 1/3,3/10 </span>
<span>8. 2/5,3/7
</span>
Answer:
1. 8/12, 9/12
<span>2. 6/10, 5/10 </span>
<span>3. 6/15, 5/15 </span>
<span>4. 25/30, 24/30 </span>
<span>5. 3/6, 4/6 </span>
<span>6. 9/21, 14/21 </span>
<span>7. 10/30, 9/30 </span>
<span>8. 14/35, 15/35</span>
Answer:
We can conclude that on this case we have identical processes but excersise 17 use another way to present the probability distribution and as we can see the expected value can be viewed as a dot product of two vectors with one vector containing the outcomes and the other the probabilities for each possible outcome.
Step-by-step explanation:
Assuming this previous info:
Exercise 17. Suppose that we convert the table on the previous page displaying the discrete distribution for the number of heads occurring when two coins are flipped to two vectors.
Let vector
There are 4 quarters in dollars. Keep that in mind.
Since Taylor is spending no more than 17 dollars, she probably only has 17 dollars. We already know that she has 8 dollars in bills, so we can subtract 8 dollars from 17 dollars because we need to find the amount of dollars in quarters.
The answer for that is 9 dollars. Since there are 4 quarters in the dollars, you need to multiply 9 by 4 to find the amount of quarters.
Answer:
B
PLZZZZZZZ GIVE ME BRAINLIEST
Step-by-step explanation:
16, 24, 32, 40, 48, 56, 64, 72, etc.
