The rational numbers are $\frac{11}{3}, 6.25, 0.01045,\sqrt{\frac{16}{81}},0.\bar{42}$ and the irrational functions are $\sqrt{48},\sqrt{\frac{3}{16}}$ .

Step-by-step explanation:

A rational number can be expressed in the form of $\frac{p}{q}$ , where p and q are integers and q is not equal to 0. For example $2,3.5,\frac{2}{5},...$ .

An irrational function can not be expressed in the form of $\frac{p}{q}$ , where p and q are integers and q is not equal to 0. For example $\sqrt{2},\sqrt{3},\sqrt{5},...$ .

If any number is multiplied by a irrational number then the resultant number is an irrational number.

By the above definition we can conclude that:

The number $\frac{11}{3}$ is a rational number.

$\sqrt{48}=\sqrt{16\times 3}=4\sqrt{3}$

Therefore $\sqrt{48}$ is an irrational number.

$6.25=\frac{625}{100}=\frac{25}{4}$

Therefore 6.25 is a rational number.

$0.01045=\frac{1045}{100000}=\frac{209}{20000}$

Therefore 0.01045 is a rational number.

$\sqrt{\frac{16}{81}}=\frac{4}{9}$

The number $\frac{16}{81}$ is a rational number.

$\sqrt{\frac{3}{16}}=\frac{\sqrt{3}}{4}$

The number $\frac{3}{14}$ is an irrational number.

$0.\bar{42}=\frac{42}{99}$

Therefore $0.\bar{42}$ is an irrational number. The numbers with recursive bar are always rational numbers.

3 0

3 years ago

Jayson baked a pan of cornbread for a family dinner. He cut the cornbread into equal size pieces. At the end of the dinner, ther

VARVARA [1.3K]

If 1/6 of the pan was left and there were 2 pieces left you just need to set 1/6 equal to 2/some number, this allows you to say that 1/6=2/x --> x/6=2-->x=12. My explanation might be a little poor since this becomes fairly fundamental later on but hopefully it helps.

7 0

3 years ago