Answer:
x= 3 inch should be turned up on each side
Step-by-step explanation:
Let the height of trough be x.
Width of trough be 12 - 2x.
and length of trough = 120 inch
Volume of trough, V = L×W×H = 120 × (12-2x) × x = 120x(12 - 2x)
For maximum volume, we find V' = 0
i.e 1440 -480x = 0
or x = 
or x= 3
Hence x= 3 inch should be turned up on each side
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
Answer:
20 5/8 yd^2
Step-by-step explanation:
width = 3 3/4 yd
length = 5 1/2 yd
First change both measurements to fractions.
3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4
5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2
area = length * width
area = 15/4 yd * 11/2 yd
area = (15 * 11)/(4 * 2) yd^2
area = 165/8 yd^2
165/8 = 20 remainder 5
area = 20 5/8 yd^2
Tbh 8778188778654789644477 I’m am a 90 old man
