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Naddika [18.5K]
3 years ago
11

Using the digits​ 0, 1,​ 2, ...8,​ 9, determine how many 6​-digit numbers can be constructed according to the following criteria

.
The number must be odd and greater than 600,000​; digits may be repeated.

The number of 6​-digit numbers that can be constructed is .........
Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer:

  • <u>200,000</u><em> 6-digit numbers can be constructed.</em>

Explanation:

Since the number is greater than 600,000, the first digit must be 6, 7, 8, or 9, so 4 different options: 4

The second, third, fourth, and fith digits can be either number 0 through 9, so 10 options for each one: 10 × 10 × 10 × 10.

Since the number must be odd and greater than 600,00, the last digit is odd, so it can be 1, 3, 5, 7, or 9, so 5 different options: 5.

Using the multiplication counting principle, you muliply the independent options to obtain the number of different combinations:

  • 4 × 10 × 10 × 10 × 10 × 5 = 200,000.
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morpeh [17]

Answer:

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3 years ago
What number is missing from the table of equivalent ratios? A) 2 B) 5 C) 7 D) 13 nt
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3 0
3 years ago
Read 2 more answers
Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the
guapka [62]

Answer:

The maximum number of packages that can be made  with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

<em>To find the G.C.F., we will list down the prime factors of each.</em>

48=2\times 2\times 2\times 2\times 3

30=2\times 3\times 5

We find that the G.C.F. = 2\times 3 = 6

Thus, the maximum number of packages that can be made  with each package have same number of each item is = 6

4 0
3 years ago
Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2
Basile [38]

Answer:

A

f(x) = x^3 - 2x^2 -3x + 6

Step-by-step explanation:

According to the Factor Theorem, if (<em>x</em> - <em>k</em>) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let <em>k</em> = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

\displaystyle f(x) = x^3 - 2x^2 - 3x + 6

Testing all three values yields that:

\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle  f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0   \end{aligned}

Hence, our answer is A.

3 0
3 years ago
Seven less than the product of 8 and a number equals 4
Vlad1618 [11]

Answer:

11/8 or 1 3/8 or 1.375

Step-by-step explanation:

From the information given by the question, we can form an equation:

Let us call the number 'n'

8 × n - 7 = 4

We then move the 7 to the other side, changing it from minus to plus:

8 × n = 4 + 7

So,

8 × n = 11

We divide both sides by 8, to leave n on one side of the equation.

n = 11/8

Therefore, n = 11/8 or 1 3/8 or 1.375

3 0
3 years ago
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