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3 years ago

The diameter of a circle is 14 inches. Find the circumstance and area use 22/7

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

3 0

Answer:

Circumference= 44 in

Area= 154 in²

Step-by-step explanation:

$\boxed{circumference \: of \: circle = 2\pi r}$

Radius

= diameter ÷2

= 14 ÷2

= 7 in

Circumference of circle

$= 2( \frac{22}{7} )(7)$

= 44 in

$\boxed{area \: of \: circle = \pi {r}^{2} }$

Area of circle

$= \frac{22}{7} ( {7}^{2} )$

= 154 in²

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3 years ago

How to find the surface area and volume of a square

3241004551 [841]

Given:

The shape is square.

To find:

The surface area and volume of a square.

Explanation:

The length of each side of the square is "a" units.

The formula for the surface area of the square is,

$\begin{gathered} Surface\text{ area = 6}\times Area\text{ of the square} \\ S.A=6a^2\text{ square units} \end{gathered}$

The formula for the volume of the square is,

$\begin{gathered} Volume,\text{ V= Length }\times breadth\times Height \\ =a\times a\times a\text{ cubic units} \\ V=a^3\text{ }cubic\text{ }units \end{gathered}$

Using these formulas, we can find the surface area and the volume of the square that has side length "a" units.

For example:

Let the side length of 3cm for a square.

So, the dimensions are 3cm by 3cm by 3cm.

That is,

The Length is 3cm.

The breadth is 3cm.

The height is 3cm.

So,

$a=3cm$

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Therefore, the surface area of the square is 54 square cm.

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1 year ago

A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 3t + 9, s(0) = 0, s(1) = 20

sertanlavr [38]

Answer:

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Step-by-step explanation:

Integrating the expression that describes the acceleration of the particle gives us an expression for its velocity. Integrating the expression for its velocity, gives us the expression for its position:

$a(t) = t^2-3t+9\\\int{a(t)} \, dt=v(t) = \frac{t^3}{3}-\frac{3t^2}{2}+9t +A\\\int{v(t)} \, dt=s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +At+B$

Use the given values s(0) = 0 and s(s) = 20 to find the constants A and B:

$s(0) =0= 0-0-0 +A*0+B\\B=0\\ s(1) =20= \frac{1^4}{12}-\frac{3*1^3}{6}+\frac{9*1^2}{2} +A*1+0\\ A=15.91667\\\\s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +15.91667t$

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3 years ago

(a) An angle measures 39º. What is the measure of its complement?

Basile [38]

Answer:

a) 51 degrees

b) 134 degrees

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39+51=90

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