To be used as a conductor for heat
mol CO₂ = 9.6
mol N₂ = 4.8
mol O₂ = 0.8
mol H₂O = 8
<h3>Further explanation</h3>
Reaction
4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O
mol CO₂
mol N₂
mol O₂
mol H₂O
The equilibrium reaction that is not shown is the reaction of N₂ and O₂ to form NO:
N₂ + O₂ ⇄ 2NO
We can write an expression for the equilibrium constant. We are given the value of Kc, but we must use Kp if we are dealing with partial pressures. However, since 2 moles of gas are formed from 2 moles of gas, the value of Kc is equal to Kp so we do not need to change anything.
Kc = (Pno)²/(Pn2)(Po2) = 1.71 x 10⁻¹
We must first use the initial pressures to find the reaction quotient to decide which way the equilibrium will shift:
Q = (1.96 x 10⁻³)²/(1.96 x 10⁻³)(1.96 x 10⁻³) = 1
Since Q > Kp, the equilibrium will shift to the left. Now we can prepare an ICE table to find the equilibrium pressures:
N₂ O₂ NO
I 1.96 x 10⁻³ 1.96 x 10⁻³ 1.96 x 10⁻³
C +x +x -2x
E 0.00196 + x 0.00196 + x 0.00196 - 2x
We enter these equilibrium pressures into the equilibrium expression and solve for x:
0.171 = (0.00196 - 2x)²/(0.00196 + x)²
Expand the equation and simplify to a quadratic function:
3.829x² - 0.00851x + 3.183·10⁻⁶ = 0
x = ((0.00851) +/- sqrt((0.00851)² - 4(3.829)(3.183 x 10⁻⁶)))/2(3.829)
x = 0.000476 atm
Now we can solve for the equilibrium partial pressures:
Pno = 0.00196 - 2(0.000476) = 0.00101 atm
Pn2 = 0.00196 + 0.000476 = 0.00244 atm
Po2 = 0.000196 + 0.000476 = 0.00244 atm
Therefore, the equilibrium partial pressure of NO is 0.00101 atm.
The potassium chloride is KCl. The gram formula mass of KCl is 39+35.5=74.5 g/mol which means 74.5 g per mole of KCl. So the mass of KCl is 6.90*74.5=514 g.
Yes steel is like bituminous coal and iron superheated then mixed together
