CaCl₂ → Ca²⁺ + 2Cl⁻
∑=1+2=3
D) 3 mol
Answer: i might be wrong but i feel like it’s A. wind blowing at 3km/h just because “ energy of an object is the energy that it possesses due to its motion.”
Explanation:
Answer:
P(mixture) = 1.92 atm
Explanation:
Given data:
Mass of H₂ = 0.200 g
Mass of N₂ = 1.00 g
Mass of Ar = 0.820 g
Volume = 2 L
Temperature = 20°C
Pressure of mixture = ?
Solution:
Pressure of hydrogen:
Number of moles of hydrogen = mass / molar mass
Number of moles of hydrogen = 0.200 g / 2 g/mol
Number of moles of hydrogen = 0.1 mol
P = nRT / V
P = 0.1 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 2.41 atm. L /2 L
P = 1.2 atm
Pressure of nitrogen:
Number of moles of nitrogen = mass / molar mass
Number of moles of nitrogen = 1 g / 28 g/mol
Number of moles of nitrogen = 0.04 mol
P = nRT / V
P = 0.04 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 0.96 atm. L /2 L
P = 0.48 atm
Pressure of argon:
Number of moles of argon = mass / molar mass
Number of moles of argon = 0.820 g / 40 g/mol
Number of moles of argon = 0.02 mol
P = nRT / V
P = 0.02 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 0.48 atm. L /2 L
P = 0.24 atm
Total pressure of mixture:
P(mixture) = pressure of hydrogen + pressure of nitrogen + pressure of argon
P(mixture) = 1.2 atm + 0.48 atm + 0.24 atm
P(mixture) = 1.92 atm
Answer:
Methane
Explanation:
The gas that you could keep in an outdoor storage tank in winter in Alaska is Methane.
The reason is the extreme low temperature during the winter. The boiling point of butane is 44 ºF ( -1ºC) and that of propane is a higher -43.6 º F but still within the range of average minimum winter temperature in Alaska (-50 ªF). Therefore we will have condensation in the tanks and not enough gas pressure.
Methane having a boling point of -259 ºF will not condense at the low wintertime temperatures in Alaska.
